Kevin-
What is the Record Source of the form you're trying to open? (SQL if a query; field names if a table) What is the Record Source of the form where this code is running?
John Viescas, Author
Effective SQL
SQL Queries for Mere Mortals
Microsoft Access 2010 Inside Out
Microsoft Access 2007 Inside Out
Microsoft Access 2003 Inside Out
Building Microsoft Access Applications
(Paris, France)
On May 18, 2017, at 2:21 PM, qing qing qingqinga@yahoo.com [MS_Access_Professionals] <MS_Access_Professionals@yahoogroups.com> wrote:
John-
I want the filter to work as:
The "CoachOperatorID" is stored under FilterID.
I am not able to figure out where and how many "" I need to get the effect of:
"CoachOperatorID=" & EmployeeID
Best Regards,
Kevin
Kevin Zhao
On Thu, May 18, 2017 at 7:50 PM +0800, "John Viescas JohnV@msn.com [MS_Access_Professionals]" <MS_Access_Professionals@yahoogroups.com> wrote:
Why do you want that? That will still result in:
John Smith = 55
It will fail trying find a field named "John" or "Smith". And even if you managed to get:
"John Smith" = 55
.. that will always be false and return no rows.
John Viescas, AuthorEffective SQLSQL Queries for Mere MortalsMicrosoft Access 2010 Inside OutMicrosoft Access 2007 Inside OutMicrosoft Access 2003 Inside OutBuilding Microsoft Access Applications(Paris, France)
On May 18, 2017, at 1:33 PM, qing qing qingqinga@yahoo.com [MS_Access_Professionals] <MS_Access_Professionals@yahoogroups.com> wrote:
John-
Yes, John Smith='55 is the result after debug.print.
How to get this? "John Smith =" & 55
Best Regards,
Kevin
Kevin Zhao
On Thu, May 18, 2017 at 7:19 PM +0800, "qing qing qingqinga@yahoo.com [MS_Access_Professionals]" <MS_Access_Professionals@yahoogroups.com> wrote:
John-
This is a long story. Let me organize my word to make it short and easy to understand.
I have table named tblEmployMenu which stores the form names.
tblEmployeeMenu
EMID
EmployeeID
EMFormName
FilterID
FormType
tblFormType
FTID
FormType
e.g. Data in tblFormType
1 edit
2 read only
3 filter by ID
So in the tblEmployeeMenu, If FormType is 3, Employee(user) can open the form vie filter which matches the FilterID (e,g.CoachOperatorID) of the opening form, and the "EmployeeID" of the current user. The EmployeeID is behind the frmEmployeeMenu, and it opens all the time.
Sorry for my poor English. I hope you may read me well enough by now. Thanks a lot for your patience.
Kevin Zhao
On Thu, May 18, 2017 at 6:37 PM +0800, "John Viescas JohnV@msn.com [MS_Access_Professionals]" <MS_Access_Professionals@yahoogroups.com> wrote:
If you look at strWhere (perhaps by doing a Debug.Print), it looks like:
'John Smith='55
That is not a valid predicate, so you'll either get an error or no rows.
Also, the arguments for OpenForm are:
FormName, View, FilterName, WhereCondition, DataMode, WindowMode, OpenArgs
The fifth argument probably should be one of the data modes, like acFormEdit, not acFotm. Are you trying to specify the View? I prefer to use named arguments to avoid having to count commas, like this:
DoCmd.OpenForm "frmGroupList, WhereCondition:=strWhere, View:=acNormal, WindowMode:=acDialog
Notice that you don't have to specify the arguments in order, and by using the parameter names, it's easier to see what it going on.
What is in IDName and EmployeeID? What is the name of the field you're trying to filter, and what does it contain?
John Viescas, AuthorEffective SQLSQL Queries for Mere MortalsMicrosoft Access 2010 Inside OutMicrosoft Access 2007 Inside OutMicrosoft Access 2003 Inside OutBuilding Microsoft Access Applications(Paris, France)
On May 18, 2017, at 12:08 PM, qing qing qingqinga@yahoo.com [MS_Access_Professionals] <MS_Access_Professionals@yahoogroups.com> wrote:
Dear All,
I would like to get the result of:
"SomeID=" & Me.EmployeeID as a filter
I have a text field IDName stores the name of the "SomeID" as title not as value.
So I wrote something like:
strWhere=""" & IDName & "="" & Me.EmployeeID
Then I apply it as this:
DoCmd.OpenForm "frmGroupList", , strWhere, , acFotm, acDialog
I didn't get the result I expected. Please help, Thanks.
Best Regards,
Kevin
Kevin Zhao
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Posted by: John Viescas <johnv@msn.com>
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