Thanks Bill!! It works great!
Katrina
--- In MS_Access_Professionals@yahoogroups.com, "Bill Mosca" <wrmosca@...> wrote:
>
> Katrina
>
>
>
> The key word DISTINCT goes right after the word SELECT as in:
>
>
>
> SELECT DISTINCT CustName
>
> FROM MyTable
>
>
>
> But keep in mind if you have more than one field in the SELECT clause all of
> those fields are taken into consideration.
>
> Let's say you have 3 customers named Joe in different states.
>
>
>
> If you wrote:
>
> SELECT DISTINCT CustName
>
> FROM MyTable
>
> WHERE CustName = 'Joe'
>
>
>
> It would return only one record. However if you wrote:
>
> SELECT DISTINCT CustName, State
>
> FROM MyTable
>
> WHERE CustName = 'Joe'
>
>
>
> It would return all 3: Joe from California, Joe from Washington (a less cool
> state) and Joe from Arizona (an even less cool state). You get 3 records because
> it's the combination of both fields that make a record distinct in this case.
>
>
>
> To use DISTINCT in the query designer open the query and switch to SQL view.
> Then just type in the DISTINCT as I have shown above.
>
>
>
>
>
> Regards,
> Bill Mosca,
> Founder, MS_Access_Professionals
> That'll do IT <http://thatlldoit.com/> http://thatlldoit.com
> MS Access MVP
> <https://mvp.support.microsoft.com/profile/Bill.Mosca>
> https://mvp.support.microsoft.com/profile/Bill.Mosca
>
>
>
> From: MS_Access_Professionals@yahoogroups.com
> [mailto:MS_Access_Professionals@yahoogroups.com] On Behalf Of ka0t1c_ang3l
> Sent: Thursday, January 26, 2012 2:22 PM
> To: MS_Access_Professionals@yahoogroups.com
> Subject: [MS_AccessPros] Re: Combo Box used for parameter query, form, and
> report
>
>
>
>
>
> I've done some research online and have found that if I set the query to a
> DISTINCT query it will remove the duplicates. However, I'm not very Access savy
> and don't know where exactly this should go.
>
> Any help is appreciated!
>
> Thanks!
>
> Katrina
>
> --- In MS_Access_Professionals@yahoogroups.com
> <mailto:MS_Access_Professionals%40yahoogroups.com> , ka0t1c_ang3l <no_reply@>
> wrote:
> >
> > Crystal,
> >
> > Np! I'm more than happy to share with everyone else. I did run into a problem
> that I can't seem to figure out how to do, or I've just been working on this
> database TOO long. I've entered my invoice information and some invoices have
> the same project #. Therefore, when I'm trying to run a report based on query
> that groups all the project #'s together, in the drop down menu the same project
> #'s are displayed multiple times because there's that many invoices with the
> same project number. How can I keep duplicates from being displayed in the drop
> down menu and have it displayed only once, yet would not delete out any records?
> >
> > I hope that makes sense!
> >
> > Thanks!
> >
> > Katrina
> >
> > --- In MS_Access_Professionals@yahoogroups.com
> <mailto:MS_Access_Professionals%40yahoogroups.com> , Crystal <strive4peace2008@>
> wrote:
> > >
> > > Hi Katrina,
> > >
> > > thanks for posting your solution :) glad you got it
> > >
> > >
> > > Warm Regards,
> > > Crystal
> > >
> > > Microsoft MVP
> > > remote programming and training
> > >
> > > Access Basics by Crystal
> > > http://www.AccessMVP.com/strive4peace
> > > Free 100-page book that covers essentials in Access
> > >
> > > *
> > > (: have an awesome day :)
> > > *
> > >
> > >
> > >
> > >
> > > ________________________________
> > > From: ka0t1c_ang3l
> > >
> > > I found my error! I forgot to add in the code for the function.
> > >
> > > Option Compare Database
> > > Option Explicit
> > > Public bInReportOpenEvent As Boolean ' Is report in the Open event?
> > >
> > > Function IsLoaded(ByVal strFormName As String) As Boolean
> > > ' Returns True if the specified form is open in Form view or Datasheet view.
> > > Dim oAccessObject As AccessObject
> > >
> > > Set oAccessObject = CurrentProject.AllForms(strFormName)
> > > If oAccessObject.IsLoaded Then
> > > If oAccessObject.CurrentView <> acCurViewDesign Then
> > > IsLoaded = True
> > > End If
> > > End If
> > >
> > > End Function
> > >
> > > Thanks!
> > >
> > > Katrina
> > >
> > >
> > > --- In MS_Access_Professionals@yahoogroups.com
> <mailto:MS_Access_Professionals%40yahoogroups.com> , ka0t1c_ang3l <no_reply@>
> wrote:
> > > >
> > > > I created a custom dialog box (Vendor Dialog Box) that has a combo box and
> I have a query that will be the recordsource of this combo box. I've also
> created a report based on this query. What I want is when the report is opened
> it will open the Vendor Dialog Box and allow the user to select a vendor from
> the drop down menu, and based on that selection the report will be displayed. I
> have added my capital project invoice log into the AssistantNeeded folder.
> > > >
> > > > I'm receiving a compile error: sub or function not defined. The following
> is the code I'm using and I'm getting the error on the IsLoaded portion of the
> code:
> > > >
> > > > Option Compare Database
> > > >
> > > > Private Sub Report_Close()
> > > > DoCmd.Close acForm, "Vendor Dialog Box"
> > > > End Sub
> > > >
> > > > Private Sub Report_Open(Cancel As Integer)
> > > > ' Set public variable to true to indicate that the report
> > > > ' is in the Open event
> > > > bInReportOpenEvent = True
> > > >
> > > > ' Open Vendor Dialog Box
> > > > DoCmd.OpenForm "Vendor Dialog Box", , , , , acDialog
> > > >
> > > > ' Cancel Report if User Clicked the Cancel Button
> > > > If IsLoaded("Vendor Dialog Box") = False Then Cancel = True
> > > >
> > > > ' Set public variable to false to indicate that the
> > > > ' Open event is completed
> > > > bInReportOpenEvent = False
> > > > End Sub
> > > >
> > > > Any help is appreciated!!
> > > >
> > > > Thanks!
> > > >
> > > > Katrina
> > > >
> > >
> > >
> > >
> > >
> > > ------------------------------------
> > >
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > > [Non-text portions of this message have been removed]
> > >
> >
>
>
>
>
>
> [Non-text portions of this message have been removed]
>
Jumat, 27 Januari 2012
[MS_AccessPros] Re: Combo Box used for parameter query, form, and report
__._,_.___
.
__,_._,___
Langganan:
Posting Komentar (Atom)
Tidak ada komentar:
Posting Komentar