Doyce-
You can add dates and times, like this:
SELECT DISTINCT p.PRTNUM_01, v.VENID_55, [Vendor Master].COMNAM_08 AS Comnam, v.TNXDTE_55, v.TNXTIM_55FROM ([PART MASTER] AS p INNER JOIN [PO Receipts] AS v ON p.PRTNUM_01 = v.PRTNUM_55) INNER JOIN [Vendor Master] ON v.VENID_55 = [Vendor Master].VENID_08
WHERE (((v.TNXDTE_55 + v.TNXTIM_55FROM)=(SELECT Max(TNXDTE_55 + TNXTIM_55FROM)
FROM [PO Receipts] As v2
WHERE v2.PRTNUM_55 = p.PRTNUM_01)))
ORDER BY p.PRTNUM_01;
WHERE (((v.TNXDTE_55 + v.TNXTIM_55FROM)=(SELECT Max(TNXDTE_55 + TNXTIM_55FROM)
FROM [PO Receipts] As v2
WHERE v2.PRTNUM_55 = p.PRTNUM_01)))
ORDER BY p.PRTNUM_01;
John Viescas, Author
Microsoft Access 2010 Inside Out
Microsoft Access 2007 Inside Out
Microsoft Access 2003 Inside Out
Building Microsoft Access Applications
SQL Queries for Mere Mortals
(Paris, France)
On Aug 19, 2014, at 2:08 PM, winberry.doyce@roadsysinc.com [MS_Access_Professionals] <MS_Access_Professionals@yahoogroups.com> wrote:
Hello friends,
The query below is supposed to select the last time a part was received. However I have discovered if a part is received twice on the same day, it shows up twice and I only want the latest receipt. I have added the TXNTIM_55 field but don't know how to add the max value to the query.
SELECT DISTINCT p.PRTNUM_01, v.VENID_55, [Vendor Master].COMNAM_08 AS Comnam, v.TNXDTE_55, v.TNXTIM_55FROM ([PART MASTER] AS p INNER JOIN [PO Receipts] AS v ON p.PRTNUM_01 = v.PRTNUM_55) INNER JOIN [Vendor Master] ON v.VENID_55 = [Vendor Master].VENID_08
WHERE (((v.TNXDTE_55)=(SELECT Max(TNXDTE_55)
FROM [PO Receipts] As v2
WHERE v2.PRTNUM_55 = p.PRTNUM_01)))
ORDER BY p.PRTNUM_01;
Doyce
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Posted by: John Viescas <johnv@msn.com>
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