Clive-
It looks just fine to me:
For y=1 to 12:Debug.Print y:Debug.Print DateSerial(Year(Date), Int((y - 1) / 3)
* 3 + 1, 1):next y
1
1/1/2012
2
1/1/2012
3
1/1/2012
4
4/1/2012
5
4/1/2012
6
4/1/2012
7
7/1/2012
8
7/1/2012
9
7/1/2012
10
10/1/2012
11
10/1/2012
12
10/1/2012
Int((month - 1) / 3) * 3 "rounds down" the current month to the last month of
the previous quarter, then you add 1 to get the first month of current quarter.
Int((4 - 1) / 3) = 1
Int((5 -1) / 3) = 1
Int((6 - 1) / 3) = 1
Remember, Int truncates - it doesn't round.
John Viescas, author
Microsoft Office Access 2010 Inside Out
Microsoft Office Access 2007 Inside Out
Building Microsoft Access Applications
Microsoft Office Access 2003 Inside Out
SQL Queries for Mere Mortals
http://www.viescas.com/
(Paris, France)
From: MS_Access_Professionals@yahoogroups.com
[mailto:MS_Access_Professionals@yahoogroups.com] On Behalf Of Clive
Sent: Thursday, April 12, 2012 2:55 AM
To: MS_Access_Professionals@yahoogroups.com
Subject: [MS_AccessPros] Re: DateSerial
Hi James,
No prize yet. Your function will always return the
first day of the current month.
You are subtracting 1, dividing by 3,
multiplying by 3 and adding 1.
That gives you the number you first thought of.
Try this in the Debug Window first,
For y=1 to 12:?y;tab(7);DateSerial(YearDate), Mid$("111222333444",y,1),1):next y
Regards, Clive.
--- In MS_Access_Professionals@yahoogroups.com, John Viescas <JohnV@...> wrote:
>
> James-
>
> That looks correct.
>
> John Viescas, author
> Microsoft Office Access 2010 Inside Out
> Microsoft Office Access 2007 Inside Out
> Building Microsoft Access Applications
> Microsoft Office Access 2003 Inside Out
> SQL Queries for Mere Mortals
> http://www.viescas.com/
> (Paris, France)
>
> ------------------------------
>
> From: MS_Access_Professionals@yahoogroups.com
> [mailto:MS_Access_Professionals@yahoogroups.com] On Behalf Of j1eggert
> Sent: Wednesday, April 11, 2012 7:23 PM
> To: MS_Access_Professionals@yahoogroups.com
> Subject: [MS_AccessPros] Re: DateSerial
>
>
> John,
>
> I think this is what I should have done:
>
> FirstDay = DateSerial(Year(Date), Int((Month(Date) - 1) / 3) * 3 + 1, 1)
>
> Please let me know if this is correct.
>
> Thanks,
> James Eggert
>
> --- In MS_Access_Professionals@yahoogroups.com, John Viescas <JohnV@> wrote:
> >
> > James-
> >
> > Looks like the problem is here:
> >
> > Int ((month(Date())+)/3)*3+1
> >
> > What did you mean to add to Date() inside the Month function?
> >
> > John Viescas, author
> > Microsoft Office Access 2010 Inside Out
> > Microsoft Office Access 2007 Inside Out
> > Building Microsoft Access Applications
> > Microsoft Office Access 2003 Inside Out
> > SQL Queries for Mere Mortals
> > http://www.viescas.com/
> > (Paris, France)
> >
> > ------------------------------------
> >
> > From: MS_Access_Professionals@yahoogroups.com
> > [mailto:MS_Access_Professionals@yahoogroups.com] On Behalf Of j1eggert
> > Sent: Wednesday, April 11, 2012 4:50 PM
> > To: MS_Access_Professionals@yahoogroups.com
> > Subject: [MS_AccessPros] DateSerial
> >
> >
> > I am using Access 2007 and tried to plug the following vba code into the
> Control
> > Source of a text box, which results in an error:
> >
> > =DateSerial(Year(Date()), Int ((month(Date())+)/3)*3+1,1)
> >
> > If some one could point out my error I would really appreciate it.
> >
> > v/r,
> > James Eggert
> >
>
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